Flatten Nested Dictionary

Function Name: flatten_dictionary

Description

In this challenge, you are to write a function named 'flatten_dictionary' that takes a dictionary with nested dictionaries as values and returns a new dictionary with flattened keys.

The keys in the output dictionary should be a combination of the nested keys, separated by a period ('.').

If an inner dictionary has an empty key, it should just be appended without the preceding dot.

Values from nested dictionaries are to be included in the result as is, without further nesting.

The input dictionary will only contain other dictionaries or scalar values (e.g., strings, integers).

Requirements

• The function should take one parameter: a dictionary to flatten.
• The function should return a new dictionary with no nested dictionaries, where the keys are the 'paths' from the original nested structure.
• Nested dictionaries should be flattened recursively.
• Empty keys in nested dictionaries should not lead to leading dots in the keys of the flattened dictionary.
• Handling of scalar values (non-dictionaries) within the nested dictionaries should not change.

Examples

Given the dictionary {'a': 1, 'b': {'c': 2, 'd': {'': 3, 'e': 4}}}, the function should return {'a': 1, 'b.c': 2, 'b.d': 3, 'b.d.e': 4}.Given the dictionary {'nested': {'inner': {'': 'value'}}}, the function should return {'nested.inner': 'value'}.

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